(z+4)(4z^2+z-1)=0

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Solution for (z+4)(4z^2+z-1)=0 equation: 


Simplifying
(z + 4)(4z2 + z + -1) = 0

Reorder the terms:
(4 + z)(4z2 + z + -1) = 0

Reorder the terms:
(4 + z)(-1 + z + 4z2) = 0

Multiply (4 + z) * (-1 + z + 4z2)
(4(-1 + z + 4z2) + z(-1 + z + 4z2)) = 0
((-1 * 4 + z * 4 + 4z2 * 4) + z(-1 + z + 4z2)) = 0
((-4 + 4z + 16z2) + z(-1 + z + 4z2)) = 0
(-4 + 4z + 16z2 + (-1 * z + z * z + 4z2 * z)) = 0
(-4 + 4z + 16z2 + (-1z + z2 + 4z3)) = 0

Reorder the terms:
(-4 + 4z + -1z + 16z2 + z2 + 4z3) = 0

Combine like terms: 4z + -1z = 3z
(-4 + 3z + 16z2 + z2 + 4z3) = 0

Combine like terms: 16z2 + z2 = 17z2
(-4 + 3z + 17z2 + 4z3) = 0

Solving
-4 + 3z + 17z2 + 4z3 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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